Question

Determinar o valor de "x" na equação 8^5x-1^= 32

Answer 1

8^(5x - 1) = 32

log 32 = 5x - 1
      8
log (2^5) = 5x - 1
      (2³)
5/3.log 2  = 5x - 1
            2
5/3.1 = 5x - 1
5/3 + 1 = 5x
8/3 = 5x
x = 8/15