Question

determinar o 7 termo da PG (6,12,24,...)

Answer 1

$a_n=a_1\cdot q^{n-1}$

$q=\dfrac{12}{6}=2$ e $a_1=6$

$a_7=6\cdot2^{6}$

$a_7=6\cdot64~~\Rightarrow~~a_7=384$

Answer 2

a₁ = 6
a₂ = 12
a₃ = 24
n = 7
q = 12 / 6 = 2
         a₇ = a₁ * q^n-1
         a₇ = 6 * 2⁷⁻¹
         a₇ = 6 * 2⁶
         a₇ = 6 * 64
         a₇ = 384

Espero ter ajudado. Valeu!