Question

. Determinar as coordenadas do vértice V da parábola que rerpresenta a função
f(x) = x2
– 6x + 5
XV =
Yv =

Answer 1

$\begin{array}{l}x_{v} =\frac{-b}{2a} =\frac{6}{2\cdotp 1} =3\\\\y_{v} =f( x_{v}) =f( 3) =3^{2} -6\cdotp 3+5\Longrightarrow y_{v} =-4\\\\\therefore \boxed{\boxed{V( 3,-4)}}\end{array}$