Question

determinar a10 na pg onde a5=32 e a8=256

Answer 1

$> \: resolucao \\ \\ \geqslant \: progressao \: \: geometrica \\ \\ a5 = 32 \\ a8 = 256 \\ \\ > \: a \: razao \: da \: pg \\ \\ a8 = a5 \times q {}^{3} \\ 256 = 32 \times q {}^{3} \\ \frac{256}{32} = q {}^{3} \\ 8 = q {}^{3} \\ 2 {}^{3} = q {}^{3} \\ q = 2 \\ \\ = = = = = = = = = = = = = = = = = = \\ \\ \\ > \: o \: 10 \: termo \: da \: pg \\ \\ a10 = a8 \times q {}^{2} \\ a10 = 256 \times 2 {}^{2} \\ a10 = 256 \times 4 \\ a10 = 1024 \\ \\ \\ \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \leqslant \geqslant \geqslant$