Matemática, perguntado por sarahmatos83slucrecy, 5 meses atrás

Determinar a média aritmética das sequencias de números abaixo:
a) 10, 11, 15, 25
b) 4, 4, 6, 6, 6, 9, 9, 10, 12, 15, 15, 15
c) 7, 4, 6, 3
d) 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 22
e) 1, 2, 3, 4, 5, 6, 7, 8
f) 1, 2, 2, 2, 3, 3, 4, 4, 5, 5, 5, 5, 5, 5, 6, 7, 8

Soluções para a tarefa

Respondido por auridannr
0

Explicação passo-a-passo:

a) 10, 11, 15, 25

(10 + 11 + 15 + 25 )/4 =

61/4 = 15,25

b) 4, 4, 6, 6, 6, 9, 9, 10, 12, 15, 15, 15

(4 . 2 + 8 . 3 + 9 . 2 + 10 . 1 + 12 . 1 + 15 . 3)/12 =

(8 + 24 + 18 + 10 + 12 + 45)/12 =

117/12 = 9,75

c) 7, 4, 6, 3

(7 + 4 + 6 + 3 + )/4 =

20/4 = 5

d) 8, 9, 9, 9, 9, 9, 9, 9, 9, 9, 9, 10, 22

(8 . 1 + 9 . 10 + 10 . 1 + 22 . 1)/13 =

(8 + 90 + 10 + 22)/13 =

130/13 = 10

e) 1, 2, 3, 4, 5, 6, 7, 8

(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 )/8 =

36/8 = 4,5

f) 1, 2, 2, 2, 3, 3, 4, 4, 5, 5, 5, 5, 5, 5, 6, 7, 8

(1 . 1 + 2 . 3 + 3 . 2 + 4 . 2 + 5 . 6 + 6 . 1 + 7 . 1 + 8 . 1)/17 =

(1 + 6 + 6 + 8 + 30 + 6 + 7 + 8)/17 =

72/17 = 4,23529411764706

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