Question

determinante da matriz A = (Aij)2x2, em que Aij = -i²-j

Answer 1

$A= \left[\begin{array}{cc}a11&a12\\a21&a22\end{array}\right]$

Aij=-i²-j

aij=-1²-1= 1-1= 0
aij=-1²-2= 1-2= -1
aij=-2²-1= 4-1= 3
aij=-2²-2= 4-2= 2

$A= \left[\begin{array}{cc}0&-1\\3&2\end{array}\right]$