Question

Determina o valor de x e y na igualdade
me ajudem

Answer 1

$\left[\begin{array}{ccc}x^{2}&4\\0&x+1\\\end{array}\right] - \left[\begin{array}{ccc}-2&4\\0&2\\\end{array}\right] = \left[\begin{array}{ccc}1&4\\0&0\\\end{array}\right]$

$\left[\begin{array}{ccc}x^{2} - (-2) &4-4\\0-0&x+1-2\\\end{array}\right] = \left[\begin{array}{ccc}1&4\\0&0\\\end{array}\right]$

$\left[\begin{array}{ccc}x^{2} +2 &0\\0&x-1\\\end{array}\right] = \left[\begin{array}{ccc}1&4\\0&0\\\end{array}\right]$

x-1 = 0

x = 1