Question

Determina as coordenas (x, y) do vértice da função y= 2x² +8x - 6?
ALGUÉM ME AJUDA POR FAVOR. ​

Answer 1

$y=2x^2+8x-6\Longrightarrow a=2,\ b=8,\ c=-6$

$\boxed{V(x_V,y_V)=V\bigg(-\dfrac{b}{2a},-\dfrac{b^2}{4a}+c\bigg)}$

$x_V=-\dfrac{b}{2a}=-\dfrac{8}{2(2)}\Longrightarrow \boxed{x_V=-2}$

$y_V=-\dfrac{b^2}{4a}+c=-\dfrac{8^2}{4(2)}+(-6)=-8-6\Longrightarrow\boxed{y_V=-14}$

$\mathrm{V\acute{e}rtice}\Longrightarrow\boxed{V(-2,-14)}$