Question

desenvolver produtos notaveis
(3x-7)^2
(5x+2)^2
3

Answer 1

(3x-7)²=(3x-7).(3x+7)==>3x²-3x.7-3x.7+7²==>3x²-2(3x.7)+7²


(5x+2)²=(5x+2).(5x+2)=>5x²+5x.2+5x.2+2²===>5x²+2(5x.3)+2²