Question

Desenvolver o seguinte binômio: (3x + 1)^6

Answer 1

$\displaystyle (3\text x+1)^{6} \\\\\\ \text{Desenvolvimento }\\\\ (\text a+\text b)^6=\sum_{\text k \ = \ 0 }^{ 6}{6\choose 0}\text{a}^{6-\text k}\text b^{\text k} \\\\\\ (\text a+\text b) ^6 = 1.\text{a}^6+6.\text a^{5}.\text b^1+15.\text a^4.\text b^2+20.\text a^3.\text b^3+15\text a^2.\text b^{4}+6\text a.\text b^{5}+ \text b^6$

$\displaystyle \text{temos}:\\\\ (3\text x+1)^6 \to \text a = (3\text x) \ , \ \text b = 1 \\\\\ \text{Desenvolvendo}: \\\\ (3\text x)^6+6(3\text x)^5.1+15(3\text x)^4.1+20(3\text x)^3+15(3\text x)^2+6(3\text x)^1+1 \\\\ \boxed{\ 729\text x^6+1458\text x^5+1215\text x^4+540\text x^3+135\text x^2+18\text x+1\ }\checkmark$

Answer 2

Resposta:

obrigado, tambem precisava

Explicação passo-a-passo: