Question

desenvolva o binomio (2x-3)^4? (x+a)^6 ?

Answer 1

Resposta:

$\text{Leia abaixo}$

Explicação passo-a-passo:

$\text{ Triangulo de Pascal}$

$1\\1-1\\1-2-1\\1-3-3-1 \\1-4-6-4-1\\1-5-10-10-5-1\\1-6-15-20-15-6-1$

a.

$(2x - 3)^4$

$1(2x)^4(-3)^0 + 4(2x)^3(-3)^1 + 6(2x)^2(-3)^2 + 4(2x)^1(-3)^3 + 1(2x)^0(-3)^4$

$16x^4 - 96x^3 + 216x^2 - 216x + 81$

$(2x - 3)^4 = 16x^4 - 96x^3 + 216x^2 - 216x + 81$

b.

$(x + a)^6$

$1x^6a^0 + 6x^5a^1 + 15x^4a^2 + 20x^3a^3 + 15x^2a^4 + 6x^1a^5 + 1x^0a^6$

$x^6 + 6x^5a + 15x^4a^2 + 20x^3a^3 + 15x^2a^4 + 6xa^5 + a^6$

$(x + a)^6 = x^6 + 6x^5a + 15x^4a^2 + 20x^3a^3 + 15x^2a^4 + 6xa^5 + a^6$