Question

Desenvolva a potencia (2x+y)⁵

Answer 1

Resposta:

(2x + y)⁵= 32x⁵ + 80x⁴y + 80x³y² + 40x²y³ + 10xy⁴ + y⁵

Explicação passo a passo:

(2x + y)⁵ ; (2x)⁵y⁰ + (2x)⁴y¹ + (2x)³y² + (2x)²y³ + (2x)¹y⁴ + (2x)⁰y⁵

(2x + y)⁵ = 1(2x)⁵y⁰ + 5(2x)⁴y¹ + 10(2x)³y² + 10(2x)²y³ + 5(2x)¹y⁴ + 1(2x)⁰y⁵

1.5:1=5;    5.4:2=10;    10.3:3 = 10;    10.2:4= 5;      5.1:5= 1 (obtenção dos coeficientes)

(2x + y)⁵ = 1.32x⁵.1 + 5.16x⁴y + 10.8x³y² + 10.4x²y³ + 5.2xy⁴ 1.1.y⁵

(2x + y)⁵= 32x⁵ + 80x⁴y + 80x³y² + 40x²y³ + 10xy⁴ + y⁵