Question

Descubra o valor numérico de: 4x.(3x²+2x+1)-2.(6x³+4x²+x) para x = 3/7

Answer 1

Resposta:

$\frac{6}{7}$

Explicação passo-a-passo:

Para resolver basta trocar as letras pelos números correspondentes.

$4\cdot \frac{3}{7}\left(3\left(\frac{3}{7}\right)^2+2\left(\frac{3}{7}\right)+1\right)-2\left(6\left(\frac{3}{7}\right)^3+4\left(\frac{3}{7}\right)^2+\frac{3}{7}\right)\\\\2\left(6\left(\frac{3}{7}\right)^3+4\left(\frac{3}{7}\right)^2+\frac{3}{7}\right)\\\\4\cdot \frac{3}{7}\left(3\left(\frac{3}{7}\right)^2+2\cdot \frac{3}{7}+1\right)-2\left(6\left(\frac{3}{7}\right)^3+4\left(\frac{3}{7}\right)^2+\frac{3}{7}\right)\\\\\frac{1416}{343}-\frac{1122}{343}\\\\\frac{1416-1122}{343}\\\\\frac{294}{343}\\\\\frac{6}{7}$