Question

Descubra as raízes da equação:
x^{2} + x = 6

Answer 1

x² +x -6 = 0 =>a=1, b=1, c=-6
∆= b²-4ac= 1²-4.1.(-6)=1+24= 25 => √∆=5
x = -b±√∆/2a
x = -1±5/2
x' = -1+5/2 = 4/2 = 2 ✓
x" = -1-5/2 = -6/2 = -3✓

Answer 2

${x}^{2} + x = 6 \\ {x}^{2} + x - 6 = 0 \\ a = 1 \\ b = 1 \\ c = - 6 \\ \\ d = {b}^{2} - 4ac \\ d = {1}^{2} - 4 \times 1 \times ( - 6) \\ d = 1 + 24\\ d = 25 \\ \sqrt{d} = 5 \\ \\ x1 = \frac{ - b + \sqrt{d} }{2 \times a} \\ x1 = \frac{ - 1 + 5}{2} = \frac{4}{2} = 2 \\ \\ x2 = \frac{ - b - \sqrt{d} }{2 \times a} \\ x2 = \frac{ - 1 -5 }{2} = \frac{ - 6}{2} = - 3$

Espero ter ajudado!! ^_^