descobre o termo e a a 6
Anexos:
![](https://pt-static.z-dn.net/files/d5f/00e513cb18ec5fd7fe2a68ac8388914d.jpg)
Soluções para a tarefa
Respondido por
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6.1 o termo que falta é 14, pois 1/7 vezes 2 é 2/14
6.2 o termo que falta é 16, pois 2/3 vezes 8 é 16/24
6.2 o termo que falta é 16, pois 2/3 vezes 8 é 16/24
matilde14:
brigada
Respondido por
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Vamos dizer que o temo desconhecido seja x.
Então:
![a)~~ \dfrac{1}{7} = \dfrac{2}{x} \to~~~multiplique~~cruzado.\\ \\ {\it (Repita~~ esse~~processo~~em~~todas)}\\\\ x = 7.2\to~~\boxed{x=14} a)~~ \dfrac{1}{7} = \dfrac{2}{x} \to~~~multiplique~~cruzado.\\ \\ {\it (Repita~~ esse~~processo~~em~~todas)}\\\\ x = 7.2\to~~\boxed{x=14}](https://tex.z-dn.net/?f=a%29%7E%7E+%5Cdfrac%7B1%7D%7B7%7D+%3D+%5Cdfrac%7B2%7D%7Bx%7D+%5Cto%7E%7E%7Emultiplique%7E%7Ecruzado.%5C%5C+%5C%5C+%7B%5Cit+%28Repita%7E%7E+esse%7E%7Eprocesso%7E%7Eem%7E%7Etodas%29%7D%5C%5C%5C%5C+x+%3D+7.2%5Cto%7E%7E%5Cboxed%7Bx%3D14%7D)
![b)~~ \dfrac{2}{3} = \dfrac{x}{24} \to~~3x=2.24\to~~3x=48\to~~x= \dfrac{48}{3} \to~~\boxed{x=16}\\\\\\\\\\ c)~~ \dfrac{10}{25} = \dfrac{4}{x} \to~~10x=25.4\to~~10x=100\to~~x= \dfrac{100}{10} \to~~ \boxed{x=10} b)~~ \dfrac{2}{3} = \dfrac{x}{24} \to~~3x=2.24\to~~3x=48\to~~x= \dfrac{48}{3} \to~~\boxed{x=16}\\\\\\\\\\ c)~~ \dfrac{10}{25} = \dfrac{4}{x} \to~~10x=25.4\to~~10x=100\to~~x= \dfrac{100}{10} \to~~ \boxed{x=10}](https://tex.z-dn.net/?f=b%29%7E%7E++%5Cdfrac%7B2%7D%7B3%7D+%3D+%5Cdfrac%7Bx%7D%7B24%7D+%5Cto%7E%7E3x%3D2.24%5Cto%7E%7E3x%3D48%5Cto%7E%7Ex%3D+%5Cdfrac%7B48%7D%7B3%7D+%5Cto%7E%7E%5Cboxed%7Bx%3D16%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%5C+c%29%7E%7E+++%5Cdfrac%7B10%7D%7B25%7D+%3D+%5Cdfrac%7B4%7D%7Bx%7D+%5Cto%7E%7E10x%3D25.4%5Cto%7E%7E10x%3D100%5Cto%7E%7Ex%3D+%5Cdfrac%7B100%7D%7B10%7D+%5Cto%7E%7E+%5Cboxed%7Bx%3D10%7D+)
Então:
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