Question

Desafio! Binômio De Newton
Calcule o Valor Da Soma:
(5)+(5)+(5)+(5)+(5)
(0)+(1)+(3)+(4)+(5)

Answer 1

$(_0^5)=\frac{5!}{(5-0)!0!}=\frac{5!}{5!}=1\\ \\ (_1^5)=\frac{5!}{(5-1)!1!}=\frac{5.4!}{4!}=5\\ \\ (_3^5)=\frac{5!}{(5-3)!3!}=\frac{5.4.3!}{2!3!}=\frac{20}{2}=10\\ \\ (_4^5)=(_1^5)=5\\ \\ (_5^5)=(_0^5)=1\\ \\ 1+5+10+5+1=22$