Question

dertemine os zeros da funçao f(x)=x2-4x+3

Answer 1

x^2-4x+3=0
delta=b^2-4ac
delta=(-4)^2-4.1.3
delta=16-12
delta=4
x=-b-/+ raiz de delta/2a
x=-(-4)-2/2.1
x=4-2/2
x=2/2
x=1
x=-(-4)+2/2.1
x=4+2/2
x=6/2
x=3
S={(1, 3)}

Answer 2

x² - 4x + 3 = 0

a = 1
b = -4
c = 3

Delta:
Δ = b² - 4ac
Δ = (-4)² - 4 * 1 * 3
Δ = 16 - 12
Δ = 4
      Bhaskara:
      x = - b ± √Δ / 2a
      x = - (-4) ± √4 / 2 * 1
      x = 4 ± 2 / 2
      x' = 4 + 2 / 2 = 6 / 2 = 3
      x'' = 4 - 2 / 2 = 2 / 2 = 1

S = {1, 3}

Espero ter ajudado. Valeu!