Question

derive implicitamente
sen(x)+cos(y)=sen(X).cos)(y)

Answer 1

d/dx [ sen(x) + cos (y) ] = d/dx [ sen(x) cos(y) ]

d/dx [ sen(x) ] + d/dx [ cos(y) ] = d/dx [ cos(x) ] * sen(x) + cos (y) * d/dx [ sen (x) ]

cos (x) + ( -sen(y) ) * d/dx [ y ] = ( -sen(x) ) * d/dx [ y ] * sen(x) + cos(x) cos(y)

cos (x) - y' sen(y) = cos(y) cos(x) - y' sen(y) sen(x)