Question

Derivadas ordinária
Como derivar estas funções?

f(x)=3$x^4$

f(x)=$^3 \sqrt{x}^2$

Answer 1

$f(x)=3x^{4}\\f'(x)=4*3x^{4-1}\\f'(x)=12x^{3}$

$f(x)=\sqrt[3]{x^{2}}\\f(x)=x^{\frac{2}{3}}\\f'(x)=(2/3)*x^{\frac{2}{3}-1}\\f'(x)=(2/3)*x^{-\frac{1}{3}}\\f'(x)=(2/3)*1/x^{\frac{1}{3}}\\f'(x)=(2/3)*1/\sqrt[3]{x^{1}}\\f'(x)=2/(3\sqrt[3]{x})$