Question

derivada; y=raiz 3x^3-x^2+In4+10

Answer 1

$y = \sqrt{3x^3-x^2+ln(4)+10}\\ u = 3x^3-x^2+ln(4)+10\\\\y'= \frac{1}{ \sqrt{u} }.u'$

Nota: regra da cadeia - f(g(x)) --> f'(g(x)) . g'(x)