Question

derivada
$f(x) = \sqrt{10 + {x}^{2} }$
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Answer 1

$u = 10 + {x}^{2} \\ y = \sqrt{u} \\ \frac{dy}{dx} = \frac{1}{2}{u}^{ - \frac{1}{2} } \times \frac{du}{dx} \\ \frac{dy}{dx} = \frac{2x}{2 \sqrt{10 + {x}^{2} } }$

simplificando

y' = x/sqrt(10 + x²)