Question

Derivada $F(x)= \frac{1} \sqrt{2+} 2x^{2} }$

Answer 1

Resolução:
f(x) = $\frac{1}{ \sqrt{2+2x^2} }$

f`(x) = - (0+2.2x)/(2√(2+2x^2))/√(2+2x^2)^2

f`(x) = - 4x/(2√(2+2x^2)^3)

bons estudos:

Answer 2

F(x) 1/√2 +2x² 

F'(x) = [1' *√2 +2x²  -  1 * (√2 +2x²)']/(√2 +2x² )²

F'(x) = { 0 * √2 +2x² - 4x * [1/2*√2 +2x²]} / (2 +2x²)

F'(x) = { - 2x / (2 +2x²)^3/2}

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16/10/2016
Sepauto
SSRC
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