Question

derivada de y=1/e^2x

Answer 1

$y = \dfrac{1}{e^{2x}}$

$y = e^{-2x}$

Veja

$f(u) = e^u$        u(x) = - 2x

$f'(u) = e^u$        u'(x) = - 2

y' = f'(u) . u'(x)

$y' = e^u . (-2)$

u = -2x

$y' = -2.e^{-2x}$

ou

$y' = \dfrac{-2}{e^{2x}}$