Question

Derivada de sen (x^4 - 2x)

Answer 1

$y=sen(x^2-2x)\\ u=x^4-2x)\\ \\ y=sen(u)\\ \\ \frac{dy}{dx}\frac{dy}{du}.\frac{du}{dx}=cos(u).(4x^3-2)=cos(x^4-2x)(4x^3-2)+C$