Question

derivada de f (t) = 5/2 xt2 ?

Answer 1

$f(t)\ = \frac{5xt^{2}}{2} \\\\\\usando\ regra\ das\ derivadas\ (tombo\ no\ expoente)\\\\\\f(t)'\ =2. \frac{5xt^{2-1}}{2} \\\\\\f(t)'\ = \frac{10xt}{2} \\\\\\\boxed{\boxed{f(t)'\ =5xt}}\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ ok$