Question

derivada de (1/x^2 - 3/x^4) (x+5)

Answer 1

Oi

$y=( \frac{1}{x^2} - \frac{3}{x^4} )(x+5) \\ \\ y= \frac{x}{x^2} + \frac{5}{x^2} - \frac{3x}{x^4} - \frac{15}{x^4} \\ \\ y= \frac{1}{x} + \frac{5}{x^2} - \frac{3}{x^3} - \frac{15}{x^4} \\ \\ derivando \\ \\y'=x^{-1} + 5x^{-2} - 3x^{-3} - 15x^{-4} \\ \\ y'=-x^{-2}-10x^{-3}+9x^{-4}+60x^{-5} \\ \\ \boxed{y'= -\frac{1}{x^2} -\frac{10}{x^3} + \frac{9}{x^4} + \frac{60}{x^5}} \\ \\ se \ quiser \ pode \ arrumar \\ \\ \boxed{y'= \frac{-x^3-10x^2+9x+60}{x^5}}$

Espero que goste. Comenta depois