Question

dentre os numeros 0, 1, 2, 3 quais sao as raizes da equacao x2-5x+6=0

obs x2 e x ao quadrado

Answer 1

$x^{2} - 5x + 6 = 0$

Respondendo por Bháskara

$x = \frac{-b \pm \sqrt{b^2 -4*a*c}}{2*a}$

a=1,b=-5,c=6

Δ=b2−4ac
Δ=(−5)2−4*(1)*(6)
Δ=25−24
Δ=1

$x = \frac{-b \pm \sqrt{\triangle}}{2*a}$

$x = \frac{-(-5) \pm \sqrt{1}}{2*1} \\ \\ x = \frac{5 \pm \sqrt{1}}{2} \\ \\ x = \frac{5 + 1}{2} \\ \\ x' = \frac{6}{2} \\ \\ x' = 3 \\ \\ \\ x'' = \frac{5-1}{2} \\ \\ x'' = \frac{4}{2} \\ \\ x'' = 2$

S = {2, 3}