Question

delta da funcao y=×2-10×+25

Answer 1

y=x²-10x+25

Δ=b²-4.a.c
Δ=(-10)²-4.1.25
Δ=100-4.25
Δ=100-100
Δ=0

Answer 2

y=x^2-10x+25
x^2-10x+25 =0
delta=b^2-4.a.c
delta=(-10)^2-4.1.25
delta=100-100
delta=0
y=-b-/+ raiz de delta / 2a
y=-(-10)-0/2.1
y=10-0/2
y=10/2
y=5