Question

delta, alg pfvr!
${2x}^{2} - 5 - 7x$
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Answer 1

$\Large\mathsf\displaystyle{} {2x}^{2} - 5 - 7x \\ \\\Large\mathsf\displaystyle{} {2x}^{2} - 5 - 7x = 0 \\ \Large\mathsf\displaystyle{} {2x}^{2} - 7x - 5 = 0 \\ \Large\mathsf\displaystyle{}\begin{cases}a = 2 \\ b = - 7 \\ c = - 5\end{cases} \\\\ \Large\mathsf\displaystyle{}x = \dfrac{ -\left( - 7\right) \pm \sqrt{\left( - 7\right)^{2} } - 4\cdot2 \cdot\left( - 5\right) }{2\cdot2} \\\\\Large\mathsf\displaystyle{}x = \dfrac{7 \pm \sqrt{49 + 40} }{4} \\\\ \\ \Large\mathsf\displaystyle{}x = \dfrac{7 \pm \sqrt{89} }{4} \\\\\\ \Large\mathsf\displaystyle{}x = \dfrac{7 + \sqrt{89} }{4} \\\\\\\Large\mathsf\displaystyle{}x = \dfrac{7 - \sqrt{89} }{4} \\\\ \Large\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{ x_{1} = \frac{7 + \sqrt{89} }{4} }}}\end{gathered} } \\\Large\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{ x_{2} = \frac{7 - \sqrt{89} }{4} }}}\end{gathered} }$

$\Large\mathsf\displaystyle{}\displaystyle\text{ \begin{gathered} \underline{\boxed{\boldsymbol{{ \red{Bons}} \blue{\:Estudos}}}}\end{gathered} }$