Question

DELTA

A) X²-5x+6=0

B) X²-8x+12=0

C) X²+2x-8=0

Answer 1

letra A
a=1
b=-5
c=6
D(delta)=b²-4.a.c
D=(-5)²-4.1.6
D=25-24
D=1
raiz do delta=1

letra B
a=1
b=-8
c=12
D=b²-4.a.c
D=(-8)²-4.1.12
D=64-48
D=16
raiz do delta=4

letra C
a=1
b=2
c=-8
D=b²-4.a.c
D=2²-4.1.(-8)
D=4+32
D=36
raiz do delta = 6

Answer 2

x²-5x+6=0
∆= (-5)² -4.1.6
∆= 25+(-4).6
∆=25+(-24)
∆= 1 √1= 1.

x²+2x-8=0
∆= (2)² -4.1.(-8)
∆= 4+32
∆= 36 √36= 6

x²-8x+12=0
∆= (-8)²-4.1.12
∆= 64+(-4).12
∆= 64+(-48)
∆= 16 √16=4