Question

degine a funcao inversa de : a)f(x)=2x-3/ x+3 b) f(x)=3x^2-3

Answer 1

Oi Nicolli 

a) f(x) = (2x - 3)/(x + 3)

xy + 3y = 2x - 3

xy - 2x = -3y - 3

x*(y - 2) = -3y - 3

x = (3y + 3)/(2 - y)

f-1(x) = (3x + 3)/(2 - x) 

b) f(x) = 3x^2 - 3y = 3x^2 - 3

3x^2 = y + 3

x^2 = (y + 3)/3

x1 = √((y + 3)/3)
x2 = -√((y + 3)/3)

f^-1(x) = √((x + 3)/3)
f^-1(x) = -√((x + 3)/3)