Question

Defina as raízes da função e os vértices: 2x² -x -3

Answer 1

2x²-x-3=0

a=2

b=-1

c=-3

Δ=b²-4ac

Δ=(-1)²-4.2.(-3)

Δ=1+24

Δ=25

x=-b+/-√Δ/2a

x=-(-1)+/-√25/2.2

x=1+/-5/4

x'=1+5/4=6/4 (:2) = 3/2

x"=1-5/4=-4/4=-1

S= {3/2, -1]

Vértice do eixo x:

-b/2a

-(-1)/2.2

1/4

Vértice do eixo y:

-Δ/4a

-25/4.2

-25/8

Vértices (1/4, -25/8)