Question

Dê uma conversões://///
(A) 25°C K
(B)70°F °C
(C)200°F K
(D)300K °F
(E)80°F °C
(F)100°C °F

Answer 1

T°C/5 = T°F/9 ; TK = T°C +/- 273

a) 25 + 273 = 298 K

b)Tc/5=70F-32/9 --> 9Tc=5*38

Tc=190/9 --> Tc = 21,1°C

c)Tc/5=TF - 32/9 --> Tc/5=200F-32/9

9Tc=5*168 --> Tc=840/9

Tc=93,3(+273K) = ~ 366,3K

d)300K(-273)=27°C

27C/5=TF-32/9

5Tf-32=27*9

5TF-32=243

TF-32=243/56

TF = 48,6+32=80,6°F

e)Tc/5=80F-32/9

9Tc=5*48

9Tc=240

Tc=240/9= 26,6°C

f)100C/5=TF-32/9

5TF-32=900

TF-32=900/5

TF=180+32= 212°F

Espero ter ajudado.