De termine o mmc de ( 15,3) (10,15) 18,30)( 21,12 )(35,10)( 25,80 )(140,10) 8,10,25 Pelo processo de decomposição
Soluções para a tarefa
5, 1 5
1,1 Resp. 15
10,15 2
5, 15 3
5, 5 5
1, 1 Resp. 30
Olá...
a) (15, 3) =
15, 3 / 3
5, 1/5
1, 1 =====>MMC = 2x 3 = 15
b) (10, 15) =
10, 15 / 2
5, 15 / 3
5, 5 / 5
1, 1 ====>MMC = 2 x 3 x 5 = 30
c) (18, 30) =
18, 30 / 2
9, 15 / 3
3, 5 / 3
1, 5 / 5
1, 1====>MMC = 2 x 3 x 3 x 5 = 90
d) (21,012) =
21, 12 / 3
7 , 4 / 2
7, 2 / 2
7, 1 / 7
1, 1======>MMC = 3 x 2 x 2 x 7 = 84
e) (35, 10) =
35, 10 / 2
35, 5 / 5
7, 1 / 7
1, 1=====>MMC = 2 x 5 x 7 =70
f) (25, 80) =
25,80 / 2
25, 40 / 2
25, 20 / 2
25, 10 / 2
25, 5 / 5
5, 5 / 5
1, 1====>MMC = 2 x 2 x 2 x 2 x 5 x 5 = 400
g) (140 , 10) =
140, 10 / 2
70, 5 / 2
35, 5 / 5
7 , 1 / 7
1, 1=======MMC = 2 x 2 x 5 x 7 = 140
h) (8, 10, 25) =
8, 10, 25 / 2
4, 5, 25 / 2
2, 5, 25 / 2
1, 5, 5 / 5
1, 1, 1====>MMC = 2 x 2 x 2 x 5 = 40
Espero ter contribuído, bons estudos.