Question

Dê as derivadas das funções: y=x^6+3x^4+x^2; y=4x^3-1/x+2√x; y=x^3/x^2+1; y=x^4.(√x+x^2)

Answer 1

a) y' = 6x^5 + 12x^3 + 2x

b) y' = 12x^2 + 1 / (x²) + 1 / (√x)

c) y' = [ 3x² (x² + 1) + x³(2x) ] / (x² + 1)²

d) y' = 4x³ (√x + x²) + x^4 [ 1 / (2√x) + 2x ]