Question

De acordo com as matrizes abaixo, o valor de 3.A+B1. sendo

Answer 1

Resposta:

$3 * A + B^{t} = \left[\begin{array}{ccc}6&14\\-1&-11\end{array}\right]$

Explicação passo a passo:

Calculemos a transposta de B, inicialmente

Lembre-se que a transposta transforma as linhas em colunas.

$B = \left[\begin{array}{cc}6&11\\-10&1\end{array}\right]$

$B^t = \left[\begin{array}{ccc}6&-10\\11&1\end{array}\right]$

Segue que

$\\3 * \left[\begin{array}{ccc}0&1\\3&-4\end{array}\right] + \left[\begin{array}{ccc}6&11\\-10&1\end{array}\right]$

$3 * A + B^{t} = \left[\begin{array}{ccc}0&3\\9&-12\end{array}\right] + \left[\begin{array}{ccc}6&11\\-10&1\end{array}\right] = \left[\begin{array}{ccc}6&14\\-1&-11\end{array}\right]$