Question

De a massa molar das substancias a seguir: (Co:59)(N:14)(H:1)(Cl:35)(Fé:56)(Cr:52)(C:12)(S:32)(Na:23)(Au:197)(Ni:59)
a) Co(NH3)5Cl
b) Fé(C2O4)2Cl2
c) Cr(NCS)6
d) Ni(NH3)2Br2
e) NaAU(CN)2
f) [Co(Co)2Cl2]3Fe(C2O4)3
Alguém pode me ajudar pfv!?​

Answer 1

Resposta:

a)Co(NH3)5Cl

59+(14+1×3)×5+35=

59+17×5+35=

59+85+35=179 g

b)Fe(C2O4)2Cl2

56+(12×2+16×4)×2+35×2=

56+176+70=302 g

c)Cr(NCS)6

52+(14+12+32)×6=

52+348= 400 g

d)Ni(NH3)2Br2

59+(14+1×3)2+80×2

59+34+160=253 g

e)NaAu(CN)2

23+197+(12+14)2

23+197+52= 272 g

f)[Co(Co)2Cl2]3Fe(C2O4)3

[59+59×2+35×2]×3+56+88 × 3

=[59+118+70]×3+56+264=

247×3+56+264=

741+56+264=1061 g