Matemática, perguntado por iFierz, 10 meses atrás

De a expressão geral dos ângulos congruos do angulo 1140° 970° 570° 1800°

Soluções para a tarefa

Respondido por CyberKirito
1

\mathsf{1140^{\circ}=3\times360^{\circ}+60^{\circ}}\\\huge\boxed{\boxed{\boxed{\mathsf{\alpha=60^{\circ}+k.360^{\circ}\,com\,k\in\mathbb{Z}}}}}}

970^{\circ}=2\times360^{\circ}+250^{\circ}\\\huge\boxed{\boxed{\boxed{\mathsf{\alpha=250^{\circ}+k.360^{\circ}\,com\,k\in\mathbb{Z}}}}}

\mathsf{570^{\circ}=1\times360^{\circ}+210^{\circ}}\\\huge\boxed{\boxed{\boxed{\mathsf{\alpha=210^{\circ}+k.360^{\circ}\,com\,k\in\mathbb{Z}}}}}

\mathsf{1800^{\circ}=5\times360^{\circ}+0^{\circ}}\\\huge\boxed{\boxed{\boxed{\mathsf{\alpha=0^{\circ}+k.360^{\circ}}}}}

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