Daria para resolver a questão 16 e 17?
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16) ![[(-3)^2- (-1)^{-2013} +(-2) ^{-2} ]:( \frac{2}{41})^-^1=](https://tex.z-dn.net/?f=%5B%28-3%29%5E2-+%28-1%29%5E%7B-2013%7D+%2B%28-2%29+%5E%7B-2%7D+%5D%3A%28+%5Cfrac%7B2%7D%7B41%7D%29%5E-%5E1%3D+ "[(-3)^2- (-1)^{-2013} +(-2) ^{-2} ]:( \frac{2}{41})^-^1=")
![[(-3)^2- \frac{1}{(-1) ^{2013} }+ \frac{1}{ -2^{2} }]:( \frac{41}{2})^1](https://tex.z-dn.net/?f=%5B%28-3%29%5E2-+%5Cfrac%7B1%7D%7B%28-1%29+%5E%7B2013%7D+%7D%2B+%5Cfrac%7B1%7D%7B+-2%5E%7B2%7D+%7D%5D%3A%28+%5Cfrac%7B41%7D%7B2%7D%29%5E1++++%0A "[(-3)^2- \frac{1}{(-1) ^{2013} }+ \frac{1}{ -2^{2} }]:( \frac{41}{2})^1")
![[9-(-1)+ \frac{1}{4} ]: \frac{41}{2}](https://tex.z-dn.net/?f=%5B9-%28-1%29%2B+%5Cfrac%7B1%7D%7B4%7D+%5D%3A+%5Cfrac%7B41%7D%7B2%7D+ "[9-(-1)+ \frac{1}{4} ]: \frac{41}{2}")
![\frac{41}{4} : \frac{41}{2} = \frac{41}{4}. \frac{2}{41}=<br /><br />[tex] \frac{1}{2}=0,5 (letra c)](https://tex.z-dn.net/?f=+%5Cfrac%7B41%7D%7B4%7D+%3A+%5Cfrac%7B41%7D%7B2%7D+%3D+%5Cfrac%7B41%7D%7B4%7D.+%5Cfrac%7B2%7D%7B41%7D%3D%3Cbr+%2F%3E%3Cbr+%2F%3E%5Btex%5D+%5Cfrac%7B1%7D%7B2%7D%3D0%2C5+%28letra+c%29 "\frac{41}{4} : \frac{41}{2} = \frac{41}{4}. \frac{2}{41}=<br /><br />[tex] \frac{1}{2}=0,5 (letra c)")
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