Question

Dados x2+6x+5=0 resolva por Bháskara e ache as raízes da equação
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Answer 1

Resposta:

Explicação passo-a-passo:

$\displaystyle Aplicando~a~f\'{o}rmula~de~Bhaskara~para~x^{2}+6x+5=0~~e~comparando~com~(a)x^{2}+(b)x+(c)=0,~determinamos~os~coeficientes:~\\a=1{;}~b=6~e~c=5\\\\C\'alculo~do~discriminante~(\Delta):&\\&~\Delta=(b)^{2}-4(a)(c)=(6)^{2}-4(1)(5)=36-(20)=16\\\\C\'alculo~das~raizes:&\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(6)-\sqrt{16}}{2(1)}=\frac{-6-4}{2}=\frac{-10}{2}=-5\\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(6)+\sqrt{16}}{2(1)}=\frac{-6+4}{2}=\frac{-2}{2}=-1\\\\S=\{-5,~-1\}$