Question

Dados os valores log2= 0.3010, log 3= 0,4771, log 5=0,6990 e log 7=0,8451, determine.
a) log 14
b) log 49
c) log2/3

Answer 1

a) Log14
= Log 7 * 2
= Log7 + Log2
= 0,8451 + 0,3010
= 1,1461

b) Log 49
= Log 7²
= 2 Log7
= 2 * 0,8451
= 1,6902

c) Log 2/3
= Log2 - Log3
= 0,3010 - 0,4771
= -0,1761