Question

Dados os pontos A(1,5)B(-2,1)C(8,1) Calcule a distância dab? Dab√(xb-xa)²+(yb-ya)²?

Answer 1

$x_a=1\\x_b=-2\\y_a=5\\y_b=1\\\\\\D= \sqrt{(x_b-x_a)^2+(y_b-y_a)^2}\\\\D= \sqrt{(-2-1)^2+(1+5)^2}\\\\D= \sqrt{(-3)^2+(-4)^2}\\\\D= \sqrt{9+16}\\\\D= \sqrt{25} \\\\\boxed{\boxed{D=5 }}$