Question

dados log2= 0,3010 e log3=0,4771,calcule log√60

Answer 1

Log√60

= Log 60^1/2
= 1/2 Log60
= 1/2 Log 3 * 2 * 10
= 1/2 ( Log3 + Log2 + Log10)
= 1/2 ( 0,3010 + 0,4771 + 1)
= 1/2 (1,7781)
= 0,88905