Question

dados log2=0 301 e log3 =0 477 calcule: a) log 9 b) log 12 c) log 42 d) log 48 e) log 72

Answer 1

log2=0, 301 e log3 =0, 477 calcule:

a) log 9 = log3²  ==. 2log3 ==> 2.(0,477) ==> 0,954
=====================================================
b) log 12 = log(2².3) = 2log2 + log3 ==> 2(0,301) +0,477

 0,602+0,477  ==> 1,079
================================================
c) log 42 = log(2.3.7) = log2 + log3 + log7==> 0,301+0,477 + log 7

0,778 + log7
=====================================================
d) log 48 = log(2^4.3) = 4log2 + log3 ==> 4(0,301) +0,477 

 1,204+0,477  ==> 1,681
================================================

e) log 72 =  log(2³.3²) = 3log2 + 2log3 ==> 3(0,301) + 2(0,477 )

 0,903+0,954  ==> 1,857