Question

dados log 2= X e log 3= Y, determine: log raiz cúbica de 12.

Answer 1

$12 = 2^2*3 \\ log 2=x \ e \ log3 = y \\ log \sqrt[3]{12}= log [2^{2}*3]^{ \dfrac{1}{3} } = \dfrac{1}{3}log[2^2*3]= \dfrac{1}{3}[2log2 + log3]\ = \dfrac{2}{3}*x + \dfrac{1}{3}*y$

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31/10/2015
Bons estudos. 
SSRC - Sepauto
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