Question

dados log 2=0,301, log de 3 = 0,477, log 5= 0,699 e log 7=0,845, calcule:

a) log 15

b) log 14

c) log 42

d) log (2/3)

Answer 1

log15=log(2.5)=log2+log5=0,301 +0,699=1

log14=log (2.7)=log2+log7=0,301 +0,845=1,146

log6=log(3.2)=log3+log2=0,477+0,301=0,778
Daí
log42=log (7.6)=log7+log6=0,845+0,778=1,623

log (2/3)=log2 - log3=0,301 -0,477=0,176