Question

Dados log 2=0 301 e log 3=0 477 calcule:

log 1,5

log 0,06​

Answer 1

$\mathsf{log(1,5)=log(\dfrac{3}{2})}\\\mathsf{log(1,5)=log3-log2=0,477-0,301}$

$\huge\boxed{\boxed{\mathsf{log(1,5)=0,176}}}$

$\mathsf{log0,06=log(\dfrac{2.3}{100})}\\\mathsf{log(0,06)=log(2)+log(3)-log(100)=0,301+0,477-2}$

$\huge\boxed{\boxed{\mathsf{log(0,06)=-1,222}}}$