Question

dados log 2=0,30; log 3=0,48; log 5=0,69 ,calcule:
a) log 12
b) log 15
c) log 27

Answer 1

a) log 12 =

log 2².3=

2log2+log3= 2(0,30) +0,48 =1,08

b) log 15

log(3.5)=log3+log5=0,48+0,69= 1,17

c) log 27

log3³=3.log3=3(0,48)=1,44