Question

Dados as funções , f(x) = 3x+1; g(x)=1-x² ; h(x) = x² -2,calcule:

gohof(0,2)

Answer 1

g(h(f(x)))= g(h(3x+1))=g((3x+1)^2-2)=1-((3x+1)^2)^2-2
gohof(0.2)=((3x0.2+1)^2)^2-2=(1,6^2)^2-2=65536-2=65534