Question

DADOS A=2 B=-10 C=0 QUAL E O VALOR DE ∆=B2-4.A.C E?

Answer 1

Explicação passo-a-passo:

\begin{aligned}2x^2+(-10)x&=0\\[1em]&\downarrow\\[1em]\Delta&=(-10)^2+(4\times2\times0)\\[1em]&=100+0\\[1em]&=\bold{100}\\[1em]&\downarrow\\[1em]x_1&=\frac{-(-10)+\sqrt{100}}{2\times2}\\[1em]&=\frac{-(-10)+10}{4}\\[1em]&=\frac{20}{4}\\[1em]&=\bold{5}\\[1em]&\downarrow\\[1em]x_2&=\frac{-(-10)-\sqrt{100}}{2\times2}\\[1em]&=\frac{-(-10)-10}{4}\\[1em]&=\frac{0}{4}\\[1em]&=\bold{0}\\[1em]\end{aligned}

2x

2

+(−10)x

Δ

x

1

x

2

=0

↓

=(−10)

2

+(4×2×0)

=100+0

=100

↓

=

2×2

−(−10)+√

100

=

4

−(−10)+10

=

4

20

=5

↓

=

2×2

−(−10)−√

100

=

4

−(−10)−10

=

4

0

=0